# Exercise :: 3

(b) 74.00

(c) 25.16

(d) 88.40

(e) None of these

**Ans.c**

Let the selling price of the article be 100.

∴ Profit = 26

∴ Cost price of the article = 100 – 26 = 74

∴ Reqd.% = \(\frac{34 \times 74}{100} = 25.16 \%\)

(b) 12 eggs

(c) 14 eggs

(d) 16 eggs

(e) None of these

**Ans.b**

S.P. for 1 egg = ^{5}⁄_{10} = ^{1}⁄_{2}

∴ C.P. for 1 egg = \(\frac{100}{\left (100 + 20 \right )} \times \frac{1}{2} = \frac{5}{12}\)

⇒ He bought 12 eggs for 5 rupees.

(b) 31

(c) 32

(d) 33

(e) None of these

**Ans.c**

^{1}⁄_{36} : (100 - 4) :: x : (100 + 8)

⇒ x = \(\frac{108}{96 \times 36} = \frac{1}{32}\)

He sells 32 oranges per rupee.

(b) 1000

(c) 1500

(d) 2000

(e) None of these

**Ans.b**

C.P. for one coconut = ^{150}⁄_{100} = ^{3}⁄_{2}

S.P. for one coconut = 2

Profit on one coconut = 2 - ^{3}⁄_{2} = ^{1}⁄_{2}

∴ Profit on 2000 coconut = ^{1}⁄_{2} × 2000 = 1000

(b) 10%

(c) 15%

(d) 20%

(e) None of these

**Ans.a**

Let C.P. = 100, then M. P. = 150

S.P. = 70% of 150 = 105

∴ % profit = \(\frac{105 - 100}{100} \times 100 = 5\%\)

(b) 50 per kg

(c) 80 per kg

(d) 70 per kg

(e) None of these

**Ans.b**

Let S. P. = x per kg

∴ S.P. of 2 kg of rice = 2x = Loss

Now, Loss = C.P. – S.P.

2x = 600 – 10x

⇒ x = 50 per kg

(b) 10

(c) 20

(d) 18

(e) None of these

**Ans.a**

C.P. for one orange = ^{1}⁄_{15}

Then S.P. = \(\frac{100 + 25}{100} \times \frac{1}{15} = \frac{125}{100 \times 15} = \frac{1}{12}\)

Hence S.P. for one orange = ^{1}⁄_{12}

∴ 12 oranges must be sold for a rupee

(b) 80%

(c) 60%

(d) 25%

(e) None of these

**Ans.b**

C.P. of one litre = 6

After adding water to it One has to pay 7.20 for ^{2}⁄_{3} litre of milk.

So S.P. of ^{2}⁄_{3} litre of milk = 7.20

⇒ S.P. of 1 litre of milk = \(\frac{7.20 \times 3}{2} = 10.80\)

∵ S.P. > C.P.

Hence gain = \(\frac{10.80 - 6}{6} \times 100 = \frac{4.80}{6} \times 100\)

= 0.80 × 100 = 80%

(b)

^{40}⁄

_{3}

(c) 22

(d) 10

(e) None of these

**Ans.b**

Let profit per litre = 20

So, C.P. /litre = 100

S.P. / litre = 120

On adding 10% water to the milk

C.P. / ^{9}⁄_{10} litre = 100

S.P. / ^{9}⁄_{10} litre = 120

S.P / litre = \(\frac{120 \times 10}{9} = \frac{400}{3}\)

⇒ Profit / litre = ^{400}⁄_{3} - 100 = 33.33

% by which profit increases = 33.33 – 20 = 13.3

(b) 17.40 per kg

(c) 16.5 per kg

(d) 16 per kg

(e) None of these

**Ans.b**

C.P. of 200 kg of mixture = (80 × 13.50 + 120 × 16)

= 3000.

S.P. = 116% of 3000 = (^{116}⁄_{100} × 3000) = 3480

∴ Rate of S.P. of the mixture = (^{3480}⁄_{200}) per kg

= 17.40 per kg.